[最も選択された] if y=a^x^a^x...infinity find dy/dx 230810-If y=a^x^a^x...infinity find dy/dx

If Y Ex E X E X Infinity Then Prove Dy Dx Y 1 Y Maths Continuity And Differentiability Meritnation Com

If Y Ex E X E X Infinity Then Prove Dy Dx Y 1 Y Maths Continuity And Differentiability Meritnation Com

Using these two ideas where y=e^(xlna) dy/dx = (lna)e^(xlna) now we can substitute in our initial expression y=a^x therefore dy/dx = (a^x)lna using this method, you can differentiate any function of the same form for example where y=2^x we can see that a=2 so dy/dx = 2^xln2In terms of ;

If y=a^x^a^x...infinity find dy/dx

If y=a^x^a^x...infinity find dy/dx-Example 3 Find dy/dx if y 4 xy = 10 Solving for y in terms of x is difficult if not impossible in this problem However, by implicit differentiation, we obtain The following example illustrates how implicit functions can be used to justify the fact that dxCompute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history

Example 47 Find Dy Dx Where Y At 1 T X T 1 T 2

Example 47 Find Dy Dx Where Y At 1 T X T 1 T 2

If y = ex exex∞, then (dy/dx) = (A) y (B) (1/y) (1/ 1 y) (D) (y/ 1 y) Check Answer and Solution for above question from Mathematics inTranscribed image text Find y in terms of x if dy/dx = x^4y^7 and y(0) = 7 For what xinterval is the solution defined?To ask Unlimited Maths doubts download Doubtnut from https//googl/9WZjCW If `x^y=y^x`,then find` dy/dx`

 y = x 1 C/e^x dy/dx=xy not separable, not exact, so set it up for an integrating factor dy/dx y =x the IF is e^(int dx) = e^x so e^x dy/dx e^x y =xe^x or d/dx (e^x y) =xe^x so e^x y = int xe^x \ dx qquad triangle for the integration, we use IBP int u v' = uv int u' v u = x, u' = 1 v' = e^x, v = e^x implies x e^x int e^x \ dx = x e^x e^x C so going back to triangle e^x y = x eDy x y dx In part (a) students needed to find the second derivative ;Using implicit differentiation In part (b) students were given

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 Best answer Here, y = xlog x (log x)x Let u = (log x)x, and v = xlogx ∴ ∴ y = u v dy dx = du dx dv dx d y d x = d u d x d v d x (i) u = (log x)xMoved Permanently The document has moved here

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